Strong Match — 92.4% match
based on chemical composition and mechanical property overlap.
ASTM A959 S41603 (ASTM A959:2011) and EN 10088-1 X6CrAl13 (EN 10088-1:2014) are both steel grades.
Both fall under the Stainless Steel category.
ASTM A959 S41603 is defined under ASTM International, originating from United States, while EN 10088-1 X6CrAl13 is defined under European Standard (EN), originating from Europe.
As per chemical composition, ASTM A959 S41603 vs EN 10088-1 X6CrAl13 is a 92.4% match.
Mechanical property data is not available for both grades, so this factor could not be scored.
Combined, this makes them a strong match overall at 92.4%.
Matched by chemical composition and mechanical properties, not a formal equivalence claim. Always verify against the applicable standard before substitution.
Typical Applications
ASTM A959 S41603
Wrought stainless steel products; recommended composition limits for adoption by product standards (clause 1.1)
EN 10088-1 X6CrAl13
Not documented
Key Differences
EN 10088-1 X6CrAl13 specifies Al which is not specified for ASTM A959 S41603.
Can ASTM A959 S41603 Be Substituted With EN 10088-1 X6CrAl13?
ASTM A959 S41603 and EN 10088-1 X6CrAl13 overlap closely enough on chemistry and mechanical properties that EN 10088-1 X6CrAl13 is often considered as a substitute for ASTM A959 S41603 in many applications. Always confirm the specific property range your application needs before substituting, and check with your supplier's mill certificate.
What is the difference between ASTM A959 S41603 and EN 10088-1 X6CrAl13?
EN 10088-1 X6CrAl13 specifies Al which is not specified for ASTM A959 S41603.
Can ASTM A959 S41603 be substituted with EN 10088-1 X6CrAl13?
ASTM A959 S41603 and EN 10088-1 X6CrAl13 overlap closely enough on chemistry and mechanical properties that EN 10088-1 X6CrAl13 is often considered as a substitute for ASTM A959 S41603 in many applications. Always confirm the specific property range your application needs before substituting, and check with your supplier's mill certificate.