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UNS C14500 vs UNS C12000

Related Material — 61.3% match based on chemical composition and mechanical property overlap.

UNS C14500 and UNS C12000 are both copper grades. Both fall under the Copper Alloys category. UNS C14500 is defined under Unified Numbering System (UNS), originating from United States, while UNS C12000 is defined under Unified Numbering System (UNS), originating from United States.

As per chemical composition, UNS C14500 vs UNS C12000 is a 92% match. As per mechanical properties, the match is 0%. Combined, this makes them a related material overall at 61.3%.

Frequently Compared With UNS C14500:
UNS C11000 UNS C12200 UNS C10200 UNS C10100 UNS C19400 UNS C17200
Match Breakdown
CHEMISTRY MATCH
92%
MECHANICAL MATCH
0%
OVERALL
61.3%
Specifications
Property UNS C14500 UNS C12000
Standard UNS UNS
Category Copper Alloys Copper Alloys
Cu (%) 99.90 min 99.90 min
P (%) 0.004-0.012 0.004-0.012
Te (%) 0.40-0.70 Not specified
Matched by chemical composition and mechanical properties, not a formal equivalence claim. Always verify against the applicable standard before substitution.
Mechanical Properties
Property UNS C14500 UNS C12000
Yield Strength ~205 MPa min (H02 half-hard) ~69 MPa (annealed O60)
Tensile Strength ~260 MPa min (H02 half-hard) ~220 MPa (annealed O60)
Elongation ~8% min (H02 half-hard) ~45% (annealed O60)
Note Tellurium copper, values for H02 half-hard temper per mill datasheet Phosphorized copper (low P), values for soft annealed condition
Key Differences
Can UNS C14500 Be Substituted With UNS C12000?
UNS C14500 and UNS C12000 share some compositional similarity but differ enough that substitution should not be assumed. Review the differences above carefully, and consult the applicable standard or a metallurgist before using one in place of the other.
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UNS C14500
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UNS C12000
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Frequently Asked Questions
What is the difference between UNS C14500 and UNS C12000?
UNS C14500 specifies Te which is not specified for UNS C12000.
Can UNS C14500 be substituted with UNS C12000?
UNS C14500 and UNS C12000 share some compositional similarity but differ enough that substitution should not be assumed. Review the differences above carefully, and consult the applicable standard or a metallurgist before using one in place of the other.